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NEET 2013 · Photoelectric Experiment: Intensity, Stopping Potential & Graphs

Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from NEET 2013

Q66NEET 2013Easy

Photoelectric Experiment: Intensity, Stopping Potential & Graphs

A source of light is placed at a distance of 50 cm from a photo cell and the stopping potential is found to be V0. If the distance between the light source and photo cell is made 25 cm, the new stopping potential will be:

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Answer: (b)

Halving the distance makes intensity $4$ times ( $I \propto 1/r^2$ ), but frequency is unchanged.
$eV_0 = h\nu - \phi$ is independent of intensity.
So the answer is (b) $V_0$ .

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