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MHT CET 2025 (26 Apr, Shift 1) · Doppler Effect

Doppler Effect question from MHT CET 2025 (26 Apr, Shift 1)

Q17MHT CET 2025 · 26 APR · SHIFT 1Medium

Doppler Effect

A source of sound emits sound wave of frequency ' f ' and moves towards an observer with a velocity V3\frac{V}{3} where V is the velocity of sound. If the observer moves away from the source with a velocity V5\frac{V}{5} the apparent frequency heard by him will be

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Answer: (c)

  1. Observer moving away, source approaching: f′=f V−VoV−Vsf' = f\,\dfrac{V - V_o}{V - V_s}.
  2. f′=f V−V/5V−V/3=f 4/52/3=65ff' = f\,\dfrac{V - V/5}{V - V/3} = f\,\dfrac{4/5}{2/3} = \dfrac{6}{5}f
  3. So the answer is (c) 65f\dfrac{6}{5}f.
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