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NEET 1995 (AIPMT) · Beats

Beats question from NEET 1995 (AIPMT)

Q76NEET 1995 · AIPMTMedium

Beats

A source of sound gives 5 beats per second, when sounded with another source of frequency 100 second−1100\text{ second}^{-1}. The second harmonic of the source, together with a source of frequency 205 sec−1205\text{ sec}^{-1} gives 5 beats per second. What is the frequency of the source?

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Answer: (a)

  1. n=100±5=105n = 100 \pm 5 = 105 or 95 s−195\text{ s}^{-1}.
  2. Second harmonic 2n=2102n = 210 or 190 s−1190\text{ s}^{-1}.
  3. With 205: 210−205=5210 - 205 = 5 beats (190 gives 15).
  4. So the answer is (a) 105 second−1105\text{ second}^{-1}.
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