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MHT CET 2026 (11 Apr, Shift 2) · Doppler Effect

Doppler Effect question from MHT CET 2026 (11 Apr, Shift 2)

Q6MHT CET 2026 · 11 APR · SHIFT 2Medium

Doppler Effect

A source of sound is moving towards a stationary observer with velocity ' $V_S$ ' and then moves away with velocity ' $V_S$ '. Assume that medium through which the sound waves travel is at rest. If 'V' is the velocity of sound and 'n' is the frequency emitted by the source then the difference between the apparent frequencies heard by the observer is

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Answer: (a)

Approaching: $n_1 = \dfrac{nV}{V - V_s}$ ; receding: $n_2 = \dfrac{nV}{V + V_s}$ .
$n_1 - n_2 = nV\,\dfrac{(V+V_s) - (V-V_s)}{V^2 - V_s^2} = \dfrac{2nVV_s}{V^2 - V_s^2}$
So the answer is (a).

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