Electric Field & Field Lines question from MHT CET 2024 (11 May, Shift 2)

Answer: (c)

1. Let $AB = d$. Field of sphere A at B: $E = \dfrac{kQ}{d^2}$.
2. At the midpoint (distance $d/2$ from each centre), field of A: $\dfrac{kQ}{(d/2)^2} = 4E$, directed away from A, towards B.
3. Field of the $-2Q$ sphere: $\dfrac{k(2Q)}{(d/2)^2} = 8E$, directed towards B.
4. Both are in the same direction: $E_{net} = 4E + 8E = 12E$
5. So the answer is (c) $12E$.