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MHT CET 2023 (14 May, Shift 1) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2023 (14 May, Shift 1)

Q76MHT CET 2023 · 14 MAY · SHIFT 1Medium

Thermal Radiation: Black Body, Stefan & Wien

A sphere and a cube, both of copper have equal volumes and are black. They are allowed to cool at same temperature and in same atmosphere. The ratio of their rate of loss of heat will be

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Answer: (c)

  1. Same material, same temperature and surroundings, so rate of heat loss ∝\propto surface area AA.
  2. Equal volumes: 43πr3=a3\frac{4}{3}\pi r^3 = a^3, so a=(4π3)1/3ra = \left(\frac{4\pi}{3}\right)^{1/3} r.
  3. AsAc=4πr26a2=2π/3(4π/3)2/3\frac{A_s}{A_c} = \frac{4\pi r^2}{6a^2} = \frac{2\pi/3}{(4\pi/3)^{2/3}}
  4. Cubing: (AsAc)3=8π3/2716π2/9=π6\left(\frac{A_s}{A_c}\right)^3 = \frac{8\pi^3/27}{16\pi^2/9} = \frac{\pi}{6}
  5. So the answer is (c) (π6)1/3\left(\frac{\pi}{6}\right)^{1/3}.
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