A sphere of mass 25 gram is placed on a vertical spring. It is compressed by 0.2 m using a force 5 N. When the spring is released, the sphere will reach a height of (g = 10 m/s²) (a) 6 cm (b) 8 cm (c) 10 cm (d) 2 m

Answer: (d). k = F/x = 5/0.2 = 25 N/m Stored energy = 1/2(25)(0.2)² = 0.5 J mgh = 0.5 ⇒ h = (0.5)/(0.025 × 10) = 2 m So the answer is (d) 2 m.

A sphere of mass 25 gram is placed on a vertical spring. It is… | MHT CET 2021 (21 Sep, Shift 1)

Q16MHT CET 2021 · 21 SEP · SHIFT 1Medium

Spring & Elastic Energy

A sphere of mass 25 gram is placed on a vertical spring. It is compressed by $0.2\text{ m}$ using a force $5\text{ N}$ . When the spring is released, the sphere will reach a height of $\left(\text{g} = 10\text{ m/s}^2\right)$

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Answer: (d)

$k = \frac{F}{x} = \frac{5}{0.2} = 25$ N/m
Stored energy $= \frac{1}{2}(25)(0.2)^2 = 0.5$ J
$mgh = 0.5 \Rightarrow h = \frac{0.5}{0.025 \times 10} = 2$ m
So the answer is (d) $2$ m.

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