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MHT CET 2026 (15 May, Shift 2) · Spring & Elastic Energy

Spring & Elastic Energy question from MHT CET 2026 (15 May, Shift 2)

Q4MHT CET 2026 · 15 MAY · SHIFT 2Medium

Spring & Elastic Energy

A sphere of mass 5050 gram is placed on a vertical spring. It is compressed by 0.40.4 m using a force 1010 N. When the spring is released the sphere will reach to a height of (g=10 m/s2g = 10\text{ m/s}^2)

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Answer: (b)

  1. k=Fx=100.4=25k = \frac{F}{x} = \frac{10}{0.4} = 25 N/m
  2. Stored energy =12(25)(0.4)2=2= \frac{1}{2}(25)(0.4)^2 = 2 J
  3. mgh=2⇒h=20.05×10=4mgh = 2 \Rightarrow h = \frac{2}{0.05 \times 10} = 4 m
  4. So the answer is (b) 44 m.
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