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JEE Main 2026 (2 Apr, Shift 2) · Work-Energy Theorem

Work-Energy Theorem question from JEE Main 2026 (2 Apr, Shift 2)

Q4JEE Main 2026 · 2 APR · SHIFT 2Medium

Work-Energy Theorem

A spherical ball of mass 2 kg falls from a height of 10 m and is brought to rest after penetrating 10 cm into sand.

The average force exerted by sand on the ball is _________ N.

(Take g=10 m/s2g = 10\text{ m/s}^2)

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Answer: (b)

  1. From release to rest: Wgravity+Wsand=0W_{gravity} + W_{sand} = 0.
  2. mg(h+d)=Fd⇒F=2×10×(10+0.1)0.1mg(h + d) = F d \Rightarrow F = \frac{2 \times 10 \times (10 + 0.1)}{0.1}
  3. F=2020 NF = 2020\text{ N}
  4. So the answer is (b) 2020.
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