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JEE Main 2023 (24 Jan, Shift 1) · Work-Energy Theorem

Work-Energy Theorem question from JEE Main 2023 (24 Jan, Shift 1)

Q10JEE Main 2023 · 24 JAN · SHIFT 1Medium

Work-Energy Theorem

A spherical body of mass 2 kg starting from rest acquires a kinetic energy of 10000 J at the end of 5th5^{\text{th}} second. The force acted on the body is ________ N.

Numerical answer type. Work it out, then open the answer.

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Answer: 40

  1. 12mv2=10000⇒v2=2×100002=104\frac{1}{2}mv^2 = 10000 \Rightarrow v^2 = \frac{2 \times 10000}{2} = 10^4, so v=100 m/sv = 100\text{ m/s} at t=5 st = 5\text{ s}.
  2. From rest, a=vt=1005=20 m/s2a = \frac{v}{t} = \frac{100}{5} = 20\text{ m/s}^2
  3. F=ma=2×20=40 NF = ma = 2 \times 20 = 40\text{ N}
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