A spherical conductor of radius 10 cm has a charge of 3.2 × 10-7 C… | NEET 2020 (Phase 1)

Q94NEET 2020 · PHASE 1Easy

Electric Flux & Gauss's Law

A spherical conductor of radius 10 cm has a charge of 3.2 $\times$ 10-7 C distributed uniformly. What is the magnitude of electric field at a point 15 cm from the centre of the sphere?

$\left(\frac{1}{4\pi\varepsilon_0} = 9 \times 10^{9}\text{ N m}^2/\text{C}^2\right)$

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Answer: (a)

Outside a charged sphere it acts as a point charge: $E = \frac{kQ}{r^2}$ .
$E = \frac{9\times10^{9}\times3.2\times10^{-7}}{(0.15)^2} = \frac{2880}{0.0225}$
$E = 1.28\times10^{5}$ N/C, so the answer is (a).

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