A spherical drop of liquid splits into 1000 identical spherical drops. If ' E₁ ' is the surface energy of the original drop and ' E₂ ' is the total surface energy of the resulting drops, then (E₁)/(E₂) = x/10. Then value of ' x ' is (a) 9 (b) 7 (c) 3 (d) 1

Answer: (d). 1000 r³ = R³ ⇒ r = R/10. E₂ = 1000 · 4π (R²)/(100) T = 10 · 4π R² T = 10 E₁ (E₁)/(E₂) = 1/10 = x/10 ⇒ x = 1 So the answer is (d) 1.

A spherical drop of liquid splits into 1000 identical spherical… | MHT CET 2023 (12 May, Shift 1)

Q34MHT CET 2023 · 12 MAY · SHIFT 1Medium

Splitting & Merging of Drops

A spherical drop of liquid splits into 1000 identical spherical drops. If ' $E_1$ ' is the surface energy of the original drop and ' $E_2$ ' is the total surface energy of the resulting drops, then $\frac{E_1}{E_2} = \frac{x}{10}$ . Then value of ' $x$ ' is

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Answer: (d)

$1000\, r^3 = R^3 \Rightarrow r = R/10$ .
$E_2 = 1000 \cdot 4\pi \frac{R^2}{100} T = 10 \cdot 4\pi R^2 T = 10 E_1$
$\frac{E_1}{E_2} = \frac{1}{10} = \frac{x}{10} \Rightarrow x = 1$
So the answer is (d) 1.

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