A spherical interface lens of radius R separates two media of… | JEE Main 2026 (6 Apr, Shift 1)

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Spherical Surfaces & Thin Lenses

A spherical interface lens of radius $R$ separates two media of refractive indices 1 and 1.4 respectively as shown in the figure below. A point source is placed at a distance of $4R$ in front of spherical interface. The magnitude of the magnification of point source image is ______.

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Answer: (a)

$\frac{\mu_2}{v} - \frac{\mu_1}{u} = \frac{\mu_2 - \mu_1}{R}$ with $u = -4R$ , centre in the denser side so $R > 0$ .
$\frac{1.4}{v} + \frac{1}{4R} = \frac{0.4}{R} \Rightarrow \frac{1.4}{v} = \frac{0.15}{R} \Rightarrow v = \frac{28R}{3}$
$m = \frac{\mu_1 v}{\mu_2 u} = \frac{28R/3}{1.4 \times (-4R)} = -\frac{5}{3}$
So the answer is (a) 1.66.

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