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MHT CET 2023 (12 May, Shift 2) · Terminal Velocity

Terminal Velocity question from MHT CET 2023 (12 May, Shift 2)

Q32MHT CET 2023 · 12 MAY · SHIFT 2Easy

Terminal Velocity

A spherical metal ball of radius 'rr' falls through viscous liquid with velocity 'V\mathrm{V}'. Another metal ball of same material but of radius (r3)\left(\frac{r}{3}\right) falls through same liquid, then its terminal velocity will be

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Answer: (d)

  1. Terminal velocity v∝r2v \propto r^2 for the same material and liquid.
  2. v′=V(13)2=V9v' = V\left(\frac{1}{3}\right)^2 = \frac{V}{9}
  3. So the answer is (d) V9\frac{V}{9}.
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