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NEET 2012 (AIPMT, Prelims) · Acceleration Due to Gravity

Acceleration Due to Gravity question from NEET 2012 (AIPMT, Prelims)

Q120NEET 2012 · AIPMT · PRELIMSEasy

Acceleration Due to Gravity

A spherical planet has a mass MP and diameter DP. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to

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Answer: (a)

  1. Radius R=DP2R = \frac{D_P}{2}; acceleration does not depend on mm.
  2. g=GMP(DP/2)2=4GMPDP2g = \frac{GM_P}{(D_P/2)^2} = \frac{4GM_P}{D_P^2}
  3. So the answer is (a).
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