A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of 5 m/s², the reading of the spring balance will be (a) 24 N (b) 74 N (c) 15 N (d) 49 N

Answer: (a). m = 49/9.8 = 5 kg. Reading = m(g - a) = 5(9.8 - 5) = 24 N So the answer is (a) 24 N.

A spring balance is attached to the ceiling of a lift. A man hangs… | JEE Main 2003 (AIEEE)

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Apparent Weight & Lift

A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads $49\text{ N},$ when the lift is stationary. If the lift moves downward with an acceleration of $5\text{ m/s}^{2}$ , the reading of the spring balance will be

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Answer: (a)

$m = \frac{49}{9.8} = 5$ kg.
Reading $= m(g - a) = 5(9.8 - 5) = 24$ N
So the answer is (a) 24 N.

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