Physics Circle home Student Login

Home›Chapters›Oscillations PYQs›Spring Systems›Question 2

JEE Main 2026 (24 Jan, Shift 1) · Spring Systems

Spring Systems question from JEE Main 2026 (24 Jan, Shift 1)

Q2JEE Main 2026 · 24 JAN · SHIFT 1Easy

Spring Systems

A spring of force constant 15 N/m15\text{ N/m} is cut into two pieces. If the ratio of their length is 1:31:3, then the force constant of smaller piece is  N/m\rule{3em}{0.4pt}\text{ N/m}.

Show answer and solution

Answer: (c)

  1. kL=constantkL = \text{constant}. Smaller piece has length L4\frac{L}{4}.
  2. ksmall=4×15=60 N/mk_{small} = 4 \times 15 = 60\text{ N/m}.
  3. So the answer is (c) 60 N/m.
Report a mistake

More questions on Spring Systems