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MHT CET 2023 (9 May, Shift 1) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2023 (9 May, Shift 1)

Q96MHT CET 2023 · 9 MAY · SHIFT 1Medium

Moment of Inertia & Radius of Gyration

A square lamina of side ' $b$ ' has same mass as a disc of radius ' $R$ ' the moment of inertia of the two objects about an axis perpendicular to the plane and passing through the centre is equal. The ratio $\frac{b}{R}$ is

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Answer: (b)

Square lamina about the perpendicular axis through centre: $I = \frac{Mb^2}{6}$ .
Disc: $I = \frac{MR^2}{2}$ .
$\frac{b^2}{6} = \frac{R^2}{2} \Rightarrow b^2 = 3R^2$
So the answer is (b) $\sqrt{3} : 1$ .

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