A square loop of side 15 cm is being moved towards right at a constant speed of 2 cm/s as shown in figure. The front edge enters the 50 cm wide magnetic field at t = 0. The value of induced emf in the loop at t = 10 s will be: (a) zero (b) 4.5 mV (c) 0.3 mV (d) 3 mV

Answer: (a). Distance moved in 10 s: 2 × 10 = 20 cm, so the front edge is 20 cm inside the field. Back edge is 20 - 15 = 5 cm inside; the front edge is still within the 50 cm width. The whole loop is in the field, so flux is constant and ε = 0. So the answer is (a) zero.

A square loop of side 15 cm is being moved towards right at a… | JEE Main 2024 (9 Apr, Shift 2)

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Motional EMF

A square loop of side $15\text{ cm}$ is being moved towards right at a constant speed of $2\text{ cm/s}$ as shown in figure. The front edge enters the $50\text{ cm}$ wide magnetic field at $t = 0$ . The value of induced emf in the loop at $t = 10\text{ s}$ will be:

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Answer: (a)

Distance moved in 10 s: $2 \times 10 = 20$ cm, so the front edge is 20 cm inside the field.
Back edge is $20 - 15 = 5$ cm inside; the front edge is still within the 50 cm width.
The whole loop is in the field, so flux is constant and $\varepsilon = 0$ .
So the answer is (a) zero.

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