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NEET 2006 (AIPMT) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from NEET 2006 (AIPMT)

Q127NEET 2006 · AIPMTEasy

Electric Flux & Gauss's Law

A square surface of side L metres is in the plane of the paper. A uniform electric field E⃗\vec{E}(volt/m), also in the plane of the paper is limited only to the lower half of the square surface (see figure). The electric flux in SI inits associated with the surface is

Figure

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Answer: (d)

  1. E⃗\vec E lies in the plane of the square, so it is perpendicular to the area vector.
  2. ϕ=E⃗⋅A⃗=EAcos⁡90∘=0\phi = \vec E\cdot\vec A = EA\cos90^\circ = 0, whether the field covers half or all of the surface.
  3. So the answer is (d) zero.
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