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NEET 2022 (Phase 2) · AC Basics: Peak, RMS & Average Values

AC Basics: Peak, RMS & Average Values question from NEET 2022 (Phase 2)

Q23NEET 2022 · PHASE 2Easy

AC Basics: Peak, RMS & Average Values

A standard filament lamp consumes 100 W when connected to 200 V ac mains supply. The peak current through the bulb will be:

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Answer: (b)

  1. Irms=PVrms=100200=0.5I_{rms} = \frac{P}{V_{rms}} = \frac{100}{200} = 0.5 A
  2. I0=2 Irms=1.414×0.5=0.707I_0 = \sqrt{2}\, I_{rms} = 1.414 \times 0.5 = 0.707 A
  3. So the answer is (b) 0.707 A.
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