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NEET 1998 (AIPMT) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from NEET 1998 (AIPMT)

Q113NEET 1998 · AIPMTEasy

Stationary Waves & Vibrating Strings

A standing wave having 3 nodes and 2 antinodes is formed between two atoms having a distance $1.21$ Å between them. The wavelength of the standing wave is

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Answer: (a)

3 nodes and 2 antinodes means 2 loops, with nodes at both atoms.
Each loop is $\frac{\lambda}{2}$ , so $2 \times \frac{\lambda}{2} = \lambda = 1.21$ Å.
So the answer is (a) $1.21$ Å.

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