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NEET 1994 (AIPMT) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from NEET 1994 (AIPMT)

Q117NEET 1994 · AIPMTMedium

Stationary Waves & Vibrating Strings

A stationary wave is represented by y=Asin⁡(100t)cos⁡(0.01x)y = A\sin(100t)\cos(0.01x), where yy and AA are in millimetres, tt is in seconds and xx is in metres. The velocity of the wave is

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Answer: (a)

  1. Compare with y=Asin⁡(ωt)cos⁡(kx)y = A\sin(\omega t)\cos(kx): ω=100 rad/s\omega = 100\text{ rad/s}, k=0.01 m−1k = 0.01\text{ m}^{-1}.
  2. Speed of the component waves v=ωk=1000.01=104 m/sv = \dfrac{\omega}{k} = \dfrac{100}{0.01} = 10^4\text{ m/s}.
  3. So the answer is (a) 104 m/s10^4\text{ m/s}.
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