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MHT CET 2022 (11 Aug, Shift 2) · Force due to Surface Tension

Force due to Surface Tension question from MHT CET 2022 (11 Aug, Shift 2)

Q12MHT CET 2022 · 11 AUG · SHIFT 2Medium

Force due to Surface Tension

A steel coin of thickness ' $d$ ' and density ' $\rho$ ' is floating on water of surface tension ' $T$ '. The radius of the coin $(R)$ is [ $g =$ acceleration due to gravity]

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Answer: (d)

Upward surface tension force along the rim $= 2\pi R T$ .
Weight of coin $= \pi R^2 d \rho g$ .
Balance: $R = \dfrac{2T}{\rho g d}$ . So the answer is (d).

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