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JEE Main 2023 (8 Apr, Shift 2) · Thermometry & Thermal Expansion

Thermometry & Thermal Expansion question from JEE Main 2023 (8 Apr, Shift 2)

Q41JEE Main 2023 · 8 APR · SHIFT 2Medium

Thermometry & Thermal Expansion

A steel rod of length 1 m1\text{ m} and cross sectional area 10−4 m210^{-4}\text{ m}^2 is heated from 0∘C0^\circ\text{C} to 200∘C200^\circ\text{C} without being allowed to extend or bend. The compressive tension produced in the rod is ___________ ×104 N\times 10^4\text{ N}. (Given Young's modulus of steel =2×1011 N m−2= 2 \times 10^{11}\text{ N m}^{-2}, coefficient of linear expansion =10−5 K−1= 10^{-5}\text{ K}^{-1})

Numerical answer type. Work it out, then open the answer.

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Answer: 4

  1. F=YAαΔTF = YA\alpha\Delta T
  2. F=2×1011×10−4×10−5×200=4×104F = 2\times10^{11} \times 10^{-4} \times 10^{-5} \times 200 = 4\times10^4 N
  3. So the answer is 4.
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