A steel rod with y = 2.0 × 1011 Nm−2 and α = 10−5 ⁻ 1 of length 4 m and area of cross-section 10 cm2 is heated from 0 ° C to 400 ° C without being allowed to extend. The tension produced in the rod is x × 105 N where the value of x is ____________. Numerical answer type. Work it out, then open the answer.

Answer: 8. F = YAαΔ T, with A = 10 cm² = 10⁻³ m². F = 2 × 10¹¹ × 10⁻³ × 10⁻⁵ × 400 = 8 × 10⁵ N So x = 8.

A steel rod with y = 2.0 × 1011 Nm−2 and α = 10−5 ⁻ 1 of length 4 m… | JEE Main 2021 (1 Sep, Shift 2)

Q9JEE Main 2021 · 1 SEP · SHIFT 2Easy

Thermal Stress & Breaking Stress

A steel rod with y = 2.0 $\times$ 1011 Nm−2 and $\alpha$ = 10−5 ${}^\circ\text{C}^{-}$ 1 of length 4 m and area of cross-section 10 cm2 is heated from 0 $^\circ$ C to 400 $^\circ$ C without being allowed to extend. The tension produced in the rod is x $\times$ 105 N where the value of x is ____________.

Numerical answer type. Work it out, then open the answer.

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Answer: 8

$F = YA\alpha\Delta T$ , with $A = 10\text{ cm}^2 = 10^{-3}\text{ m}^2$ .
$F = 2 \times 10^{11} \times 10^{-3} \times 10^{-5} \times 400 = 8 \times 10^5\text{ N}$
So $x = 8$ .

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Thermal Stress & Breaking Stress question from JEE Main 2021 (1 Sep, Shift 2)

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