A steel wire having a radius of 2.0 mm, carrying a load of 4 kg, is hanging from a ceiling. Given that g = 3.1 π ms–2, what will be the tensile stress that would be developed in the wire? (a) 3.1 × 106 Nm–2 (b) 6.2 × 106 Nm–2 (c) 4.8 × 106 Nm–2 (d) 5.2 × 106 Nm–2

Answer: (a). Stress = (mg)/(π r²) = 4 × 3.1ππ (2 × 10⁻³)² = 12.44 × 10⁻⁶ = 3.1 × 10⁶ N m⁻² So the answer is (a).

A steel wire having a radius of 2.0 mm, carrying a load of 4 kg, is… | JEE Main 2019 (8 Apr, Shift 1)

Q20JEE Main 2019 · 8 APR · SHIFT 1Easy

Elastic Behaviour, Stress & Strain

A steel wire having a radius of 2.0 mm, carrying a load of 4 kg, is hanging from a ceiling. Given that g = 3.1 $\pi$ ms–2, what will be the tensile stress that would be developed in the wire?

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Answer: (a)

Stress $= \frac{mg}{\pi r^2}$
$= \frac{4 \times 3.1\pi}{\pi (2 \times 10^{-3})^2} = \frac{12.4}{4 \times 10^{-6}}$
$= 3.1 \times 10^{6}\ \text{N m}^{-2}$
So the answer is (a).

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