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MHT CET 2020 (19 Oct, Shift 2) · Bar Magnet & Magnetic Moment

Bar Magnet & Magnetic Moment question from MHT CET 2020 (19 Oct, Shift 2)

Q10MHT CET 2020 · 19 OCT · SHIFT 2Easy

Bar Magnet & Magnetic Moment

A steel wire of length / has a magnetic moment MM. It is then bent into a semicircular arc. The new magnetic moment is

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Answer: (c)

  1. Pole strength m=M/ℓm = M/\ell is unchanged on bending.
  2. Semicircle: πr=ℓ⇒r=ℓ/π\pi r = \ell \Rightarrow r = \ell/\pi; end-to-end distance =2r=2ℓ/π= 2r = 2\ell/\pi.
  3. M′=Mℓ⋅2ℓπ=2MπM' = \dfrac{M}{\ell}\cdot\dfrac{2\ell}{\pi} = \dfrac{2M}{\pi}
  4. So the answer is (c) 2Mπ\frac{2M}{\pi}.
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