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NEET 2013 · Motion Under Gravity

Motion Under Gravity question from NEET 2013

Q48NEET 2013Easy

Motion Under Gravity

A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between h1, h2 and h3 is

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Answer: (d)

  1. From rest, distances in equal successive time intervals are in the ratio 1:3:51:3:5 (Galileo's law of odd numbers).
  2. h1=12g(5)2=12.5gh_1 = \frac{1}{2}g(5)^2 = 12.5g, h2=12g(102−52)=37.5gh_2 = \frac{1}{2}g(10^2-5^2) = 37.5g, h3=12g(152−102)=62.5gh_3 = \frac{1}{2}g(15^2-10^2) = 62.5g
  3. So h2=3h1h_2 = 3h_1, h3=5h1h_3 = 5h_1, i.e. h1=h23=h35h_1 = \frac{h_2}{3} = \frac{h_3}{5}.
  4. So the answer is (d).
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