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MHT CET 2026 (15 Apr, Shift 1) · Motion Under Gravity

Motion Under Gravity question from MHT CET 2026 (15 Apr, Shift 1)

Q3MHT CET 2026 · 15 APR · SHIFT 1Easy

Motion Under Gravity

A stone falls from the top of a tower of height $100$ m and at the same time another stone is projected vertically upwards from the ground with a velocity $25$ m/s. The two stones meet after

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Answer: (c)

Both stones have the same acceleration $g$ , so relative acceleration is zero.
Relative speed $= 25$ m/s, relative distance $= 100$ m
$t = \frac{100}{25} = 4$ s
So the answer is (c) 4 s.

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