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NEET 2012 (AIPMT, Mains) · Inertia, First & Second Laws

Inertia, First & Second Laws question from NEET 2012 (AIPMT, Mains)

Q36NEET 2012 · AIPMT · MAINSEasy

Inertia, First & Second Laws

A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100% more than the previous height, the momentum when it hits the ground will change by

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Answer: (b)

  1. v=2ghv = \sqrt{2gh}, so P=m2gh∝hP = m\sqrt{2gh} \propto \sqrt{h}.
  2. Height 100% more means h′=2h⇒P′=2P≈1.41Ph' = 2h \Rightarrow P' = \sqrt{2}P \approx 1.41P.
  3. Change =41%= 41\%. So the answer is (b) 41%.
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