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MHT CET 2025 (19 Apr, Shift 2) · Conservation of Energy

Conservation of Energy question from MHT CET 2025 (19 Apr, Shift 2)

Q5MHT CET 2025 · 19 APR · SHIFT 2Easy

Conservation of Energy

A stone is projected with kinetic energy E, making an angle θ\theta with the horizontal. When it reaches a highest point, its kinetic energy is

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Answer: (c)

  1. At the highest point only the horizontal velocity vcos⁡θv\cos\theta remains.
  2. KEtop=12mv2cos⁡2θ=Ecos⁡2θKE_{top} = \frac{1}{2}m v^2\cos^2\theta = E\cos^2\theta
  3. So the answer is (c) Ecos⁡2θE\cos^2\theta.
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