A stone of mass 1 kg is tied to a string 2 m long and it's rotated at constant speed of 40 m s⁻¹ in a vertical circle. The ratio of the tension at the top and the bottom is [Take g = 10 m s⁻² ] (a) 81/79 (b) 79/81 (c) 19/12 (d) 12/19

Answer: (b). mv²/r = (1 × 1600)/(2) = 800 N Top: Tt = 800 - 10 = 790 N; bottom: Tb = 800 + 10 = 810 N (Tt)/(Tb) = 79/81, so the answer is (b).

A stone of mass 1 kg is tied to a string 2 m long and it's rotated at… | MHT CET 2019 (2 May, Shift 1)

Q16MHT CET 2019 · 2 MAY · SHIFT 1Medium

Vertical Circle: Speed & Tension

A stone of mass 1 kg is tied to a string 2 m long and it's rotated at constant speed of $40\text{ m s}^{-1}$ in a vertical circle. The ratio of the tension at the top and the bottom is [Take $g = 10\text{ m s}^{-2}$ ]

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Answer: (b)

$\frac{mv^2}{r} = \frac{1 \times 1600}{2} = 800$ N
Top: $T_t = 800 - 10 = 790$ N; bottom: $T_b = 800 + 10 = 810$ N
$\frac{T_t}{T_b} = \frac{79}{81}$ , so the answer is (b).

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Vertical Circle: Speed & Tension question from MHT CET 2019 (2 May, Shift 1)

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