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MHT CET 2019 (2 May, Shift 1) · Vertical Circle: Speed & Tension

Vertical Circle: Speed & Tension question from MHT CET 2019 (2 May, Shift 1)

Q16MHT CET 2019 · 2 MAY · SHIFT 1Medium

Vertical Circle: Speed & Tension

A stone of mass 1 kg is tied to a string 2 m long and it's rotated at constant speed of 40 m s−140\text{ m s}^{-1} in a vertical circle. The ratio of the tension at the top and the bottom is [Take g=10 m s−2g = 10\text{ m s}^{-2} ]

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Answer: (b)

  1. mv2r=1×16002=800\frac{mv^2}{r} = \frac{1 \times 1600}{2} = 800 N
  2. Top: Tt=800−10=790T_t = 800 - 10 = 790 N; bottom: Tb=800+10=810T_b = 800 + 10 = 810 N
  3. TtTb=7981\frac{T_t}{T_b} = \frac{79}{81}, so the answer is (b).
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