A stone of mass 900 g is tied to a string and moved in a vertical circle of radius 1 m making 10 rpm. The tension in the string, when the stone is at the lowest point is (if π² = 9.8 and g = 9.8 m/s²): (a) 17.8 N (b) 97 N (c) 9.8 N (d) 8.82 N

Answer: (c). ω = (2π(10))/(60) = π/3, ω² = 9.8/9 ω² r = 1.089 m/s ² T = m(g + ω² r) = 0.9(9.8 + 1.089) = 9.8 N So the answer is (c) 9.8 N.

A stone of mass 900 g is tied to a string and moved in a vertical… | JEE Main 2024 (29 Jan, Shift 2)

Q10JEE Main 2024 · 29 JAN · SHIFT 2Easy

Vertical Circle: Speed & Tension

A stone of mass $900\text{ g}$ is tied to a string and moved in a vertical circle of radius $1\text{ m}$ making $10\text{ rpm}$ . The tension in the string, when the stone is at the lowest point is (if $\pi^2 = 9.8$ and $g = 9.8\text{ m/s}^2$ ):

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Answer: (c)

$\omega = \frac{2\pi(10)}{60} = \frac{\pi}{3}$ , $\omega^2 = \frac{9.8}{9}$
$\omega^2 r = 1.089$ m/s $^2$
$T = m(g + \omega^2 r) = 0.9(9.8 + 1.089) = 9.8$ N
So the answer is (c) 9.8 N.

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