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MHT CET 2026 (14 May, Shift 2) · Vertical Circle: Speed & Tension

Vertical Circle: Speed & Tension question from MHT CET 2026 (14 May, Shift 2)

Q1MHT CET 2026 · 14 MAY · SHIFT 2Easy

Vertical Circle: Speed & Tension

A stone of mass m is tied to a string and is moved in a vertical circle of radius r making 'n' r.p.m. The total tension in the string when the stone is at the lowest point is (gg = acceleration due to gravity)

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Answer: (d)

  1. ω=2πn60=πn30\omega = \frac{2\pi n}{60} = \frac{\pi n}{30} rad/s
  2. At the lowest point: T=mg+mω2rT = mg + m\omega^2 r
  3. T=m[g+π2n2r900]T = m\left[g + \frac{\pi^2 n^2 r}{900}\right], so the answer is (d).
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