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MHT CET 2025 (5 May, Shift 2) · Vertical Circle: Speed & Tension

Vertical Circle: Speed & Tension question from MHT CET 2025 (5 May, Shift 2)

Q5MHT CET 2025 · 5 MAY · SHIFT 2Easy

Vertical Circle: Speed & Tension

A stone of mass ' m ' kg is tied to a string of length ' $L$ ' $m$ and moved in a vertical circle of radius 49 cm in a vertical plane. If it completes 30 revolutions per minute, the tension in the string when it is at the lowermost point is nearly [Take $\pi^2 = 10$ and acceleration due to gravity, $g = 10\text{ m/s}^2$ ]

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Answer: (d)

$\omega = \frac{2\pi(30)}{60} = \pi$ rad/s, $\omega^2 = 10$
$T = m(g + \omega^2 r) = m(10 + 10 \times 0.49) = 14.9\,m$
$T \approx 15\,m$ N, so the answer is (d).

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