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NEET 2019 · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from NEET 2019

Q90NEET 2019Medium

Biot-Savart Law & Circular Coils

A straight conductor carrying current ii splits into two parts as shown in the figure. The radius of the circular loop is RR. The total magnetic field at the centre P of the loop is,

Figure

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Answer: (b)

Piii/4 (3/4 arc)3i/4 (1/4 arc)
  1. The current splits into a 34\frac{3}{4} arc and a 14\frac{1}{4} arc; currents are inversely proportional to length: i1=i4i_1 = \dfrac{i}{4}, i2=3i4i_2 = \dfrac{3i}{4}.
  2. Field of an arc ∝Iθ\propto I\theta: i4⋅3π2=3i4⋅π2\dfrac{i}{4}\cdot\dfrac{3\pi}{2} = \dfrac{3i}{4}\cdot\dfrac{\pi}{2}, and the two arcs give opposite directions at P, so they cancel.
  3. Both straight wires point along lines through P, so they give zero field at P.
  4. So the answer is (b) zero.
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