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MHT CET 2026 (17 Apr, Shift 2) · Motional EMF

Motional EMF question from MHT CET 2026 (17 Apr, Shift 2)

Q1MHT CET 2026 · 17 APR · SHIFT 2Easy

Motional EMF

A straight line conductor of length 0.4 m is moved with a speed of 7.07.0 ms−1^{-1} perpendicular to magnetic field of intensity 0.80.8 Wb m−2^{-2}. The induced e.m.f. across the conductor is

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Answer: (a)

  1. Motional emf ε=Blv\varepsilon = Blv.
  2. ε=0.8×0.4×7.0=2.24\varepsilon = 0.8 \times 0.4 \times 7.0 = 2.24 V
  3. So the answer is (a) 2.242.24 V.
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