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NEET 1995 (AIPMT) · Motional EMF

Motional EMF question from NEET 1995 (AIPMT)

Q59NEET 1995 · AIPMTEasy

Motional EMF

A straight line conductor of length $0.4\text{ m}$ is moved with a speed of $7\text{ m/s}$ perpendicular to a magnetic field of intensity $0.9\text{ Wb/m}^{2}$ . The induced e.m.f. across the conductor is

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Answer: (d)

$\varepsilon = Blv$
$\varepsilon = 0.9 \times 0.4 \times 7 = 2.52$ V
So the answer is (d) $2.52$ V.

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