Student Login

Home›Chapters›Moving Charges and Magnetism PYQs›Magnetic Field of Straight Wires›Question 1

MHT CET 2026 (18 Apr, Shift 2) · Magnetic Field of Straight Wires

Magnetic Field of Straight Wires question from MHT CET 2026 (18 Apr, Shift 2)

Q1MHT CET 2026 · 18 APR · SHIFT 2Easy

Magnetic Field of Straight Wires

A straight long wire is carrying current I. The ratio of magnetic field due to this wire at perpendicular distance 2 cm and 5 cm respectively from the wire is

Show answer and solution

Answer: (d)

$B = \dfrac{\mu_0 I}{2\pi r} \Rightarrow B \propto \dfrac{1}{r}$
$\dfrac{B_1}{B_2} = \dfrac{r_2}{r_1} = \dfrac{5}{2}$
So the answer is (d) $5 : 2$ .

Report a mistake

More questions on Magnetic Field of Straight Wires

The magnetic field at a distance 'r' from a long straight wire carrying current I is 0.4…MHT CET 2026 (17 Apr, Shift 2)
The magnetic field at perpendicular distance ' r ' from a long wire carrying current ' I…MHT CET 2026 (17 Apr, Shift 1)
Two parallel wires of equal lengths are separated by a distance of 3 m from each other…MHT CET 2026 (12 May, Shift 2)
Two long straight parallel wires are separated by a distance of 20 cm. Each wire carries…MHT CET 2026 (12 May, Shift 1)
Two parallel wires of equal lengths are separated by a distance of 3 m from each other…MHT CET 2026 (11 Apr, Shift 2)
A current of 30 A each flows in opposite directions in two conducting wires, placed…JEE Main 2026 (6 Apr, Shift 2)
Two parallel long wires carry currents i₁ and i₂ with i₁ > i₂. When the currents are in…MHT CET 2026 (14 May, Shift 2)
Two long parallel wires carrying currents 8 A and 15 A in opposite directions are placed…MHT CET 2026 (11 Apr, Shift 1)