Current Loop as a Magnetic Dipole question from JEE Main 2024 (9 Apr, Shift 2)

Answer: 28

1. For a magnetic strip $M = p\,l$, where $l$ is the distance between the poles. Straight: $p\,l = 44$ A m$^2$.
2. Bent into a semicircle: arc $\pi r = l$, so the poles are now a diameter apart, $2r = \frac{2l}{\pi}$.
3. $M' = p\cdot\frac{2l}{\pi} = \frac{2\times44}{22/7} = 28$
4. So $M' = 28$ A m$^2$.