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MHT CET 2023 (14 May, Shift 1) · Current Loop as a Magnetic Dipole

Current Loop as a Magnetic Dipole question from MHT CET 2023 (14 May, Shift 1)

Q42MHT CET 2023 · 14 MAY · SHIFT 1Medium

Current Loop as a Magnetic Dipole

A straight wire carrying a current (I) is turned into a circular loop. If the magnitude of the magnetic moment associated with it is 'MM', then the length of the wire will be

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Answer: (c)

  1. Wire length LL: r=L2πr = \frac{L}{2\pi}.
  2. M=Iπr2=IL24π⇒L2=4πMIM = I\pi r^2 = \frac{IL^2}{4\pi} \Rightarrow L^2 = \frac{4\pi M}{I}
  3. So the answer is (c) L=[4MπI]1/2L = \left[\frac{4M\pi}{I}\right]^{1/2}.
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