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MHT CET 2021 (23 Sep, Shift 2) · Magnetic Field of Straight Wires

Magnetic Field of Straight Wires question from MHT CET 2021 (23 Sep, Shift 2)

Q50MHT CET 2021 · 23 SEP · SHIFT 2Easy

Magnetic Field of Straight Wires

A straight wire of diameter $0.4\text{ mm}$ carrying a current of $2\text{ A}$ is replaced by another wire of 0.8 $\text{mm}$ diameter carrying the same current. The magnetic field at distance $(R)$ from both the wires is 'B $1$ ' and 'B $2$ ' respectively. The relation between B $1$ and B $2$ is

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Answer: (b)

Outside a long straight wire $B = \frac{\mu_0 I}{2\pi R}$ , which depends only on $I$ and $R$ , not on the wire's diameter.
Same $I$ and same $R$ for both wires, so $B_1 = B_2$ .
So the answer is (b) $B_1 = B_2$ .

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