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NEET 1992 (AIPMT) · Force on Current-Carrying Conductors

Force on Current-Carrying Conductors question from NEET 1992 (AIPMT)

Q72NEET 1992 · AIPMTEasy

Force on Current-Carrying Conductors

A straight wire of length 0.50.5 metre and carrying a current of 1.21.2 ampere is placed in uniform magnetic field of induction 22 tesla. The magnetic field is perpendicular to the length of the wire. The force on the wire is

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Answer: (b)

  1. F=BILsin⁡90∘F = BIL\sin 90^\circ
  2. F=2×1.2×0.5=1.2 NF = 2 \times 1.2 \times 0.5 = 1.2\text{ N}
  3. So the answer is (b) 1.2 N.
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