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MHT CET 2024 (2 May, Shift 1) · Bernoulli's Equation

Bernoulli's Equation question from MHT CET 2024 (2 May, Shift 1)

Q13MHT CET 2024 · 2 MAY · SHIFT 1Medium

Bernoulli's Equation

A streamline flow of a liquid of density ' $\rho$ ' is passing through a horizontal pipe of crosssectional area $A_1$ and $A_2$ at two ends. If the pressure of liquid is ' P ' at a point where flow speed is ' $v$ ', then pressure at another point where the flow of speed becomes 3 v is

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Answer: (d)

Bernoulli (horizontal): $P + \frac{1}{2}\rho v^2 = P' + \frac{1}{2}\rho (3v)^2$
$P' = P - \frac{1}{2}\rho(9v^2 - v^2) = P - 4\rho v^2$
So the answer is (d).

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