Student Login

Home›Chapters›Wave Motion PYQs›Stationary Waves & Vibrating Strings›Question 90

MHT CET 2019 (2 May, Shift 2) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from MHT CET 2019 (2 May, Shift 2)

Q90MHT CET 2019 · 2 MAY · SHIFT 2Easy

Stationary Waves & Vibrating Strings

A stretched string fixed at both ends has ' $m$ ' nodes, then the length of the string will be

Show answer and solution

Answer: (a)

$m$ nodes on a string fixed at both ends give $(m - 1)$ loops.
Each loop is $\lambda/2$ long, so $L = (m - 1)\dfrac{\lambda}{2}$ .
So the answer is (a) $(m - 1)\frac{\lambda}{2}$ .

Report a mistake

More questions on Stationary Waves & Vibrating Strings

A string 2.0 m long and fixed at its ends is driven by a 240 Hz vibrator. The string…JEE Main 2019 (9 Apr, Shift 2)
A stretched wire of length 260 cm is set into vibrations. It is divided into three…MHT CET 2019 (2 May, Shift 2)
A string is clamped at both the ends and it is vibrating in its 4th harmonic. The…JEE Main 2019 (9 Apr, Shift 1)
A string of length 1 m and mass 5 g is fixed at both ends. The tension in the string is…JEE Main 2019 (10 Jan, Shift 1)
The fundamental frequency of sonometer wire increases by 9 Hz, if its tension is…MHT CET 2019 (3 May, Shift 1)
A sonometer wire is in unison with a tuning fork, when it is stretched by weight w and…MHT CET 2019 (3 May, Shift 1)
A wire of length 2L, is made by joining two wires A and B of same length but different…JEE Main 2019 (8 Apr, Shift 1)
A standing wave is formed by the superposition of two waves travelling in opposite…JEE Main 2017 (9 Apr, Shift 1)