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MHT CET 2024 (2 May, Shift 2) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from MHT CET 2024 (2 May, Shift 2)

Q42MHT CET 2024 · 2 MAY · SHIFT 2Easy

Stationary Waves & Vibrating Strings

A stretched string is fixed at both ends. It is made to vibrate so that the total number of nodes formed in it is ' xx '. The length of the string in terms of the wavelength of waves formed in it is ( λ=\lambda = wavelength ))

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Answer: (d)

  1. With both ends fixed, xx nodes give (x−1)(x - 1) loops.
  2. Each loop has length λ/2\lambda/2.
  3. L=(x−1)λ2L = (x - 1)\dfrac{\lambda}{2}.
  4. So the answer is (d) (X−1)λ2(X - 1)\frac{\lambda}{2}.
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