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MHT CET 2026 (19 May, Shift 1) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from MHT CET 2026 (19 May, Shift 1)

Q7MHT CET 2026 · 19 MAY · SHIFT 1Easy

Stationary Waves & Vibrating Strings

A stretched string of length ' $L$ ' is fixed at both the ends, has ' $n$ ' nodes ( $n > 2$ ). The length of the string in terms of $n$ and wavelength $\lambda$ is

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Answer: (d)

$n$ nodes (including both ends) divide the string into $n - 1$ loops.
Each loop is $\frac{\lambda}{2}$ , so $L = (n - 1)\frac{\lambda}{2}$ .
So the answer is (d).

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