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MHT CET 2019 (2 May, Shift 2) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from MHT CET 2019 (2 May, Shift 2)

Q92MHT CET 2019 · 2 MAY · SHIFT 2Easy

Stationary Waves & Vibrating Strings

A stretched wire of length 260 cm is set into vibrations. It is divided into three segments whose frequencies are in the ratio $2:3:4$ . Their lengths must be

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Answer: (b)

$f \propto \dfrac{1}{l}$ : $l_1 : l_2 : l_3 = \dfrac{1}{2} : \dfrac{1}{3} : \dfrac{1}{4} = 6 : 4 : 3$ .
Total parts $= 13$ , each part $= \dfrac{260}{13} = 20\text{ cm}$ .
Lengths: $120, 80, 60\text{ cm}$ .
So the answer is (b) $120\text{ cm}, 80\text{ cm}, 60\text{ cm}$ .

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